{"id":9472,"date":"2020-10-14T12:52:19","date_gmt":"2020-10-14T12:52:19","guid":{"rendered":"https:\/\/samacheer-kalvi.com\/?p=9472"},"modified":"2021-12-06T16:02:41","modified_gmt":"2021-12-06T10:32:41","slug":"samacheer-kalvi-8th-maths-guide-chapter-7-ex-7-2","status":"publish","type":"post","link":"https:\/\/samacheer-kalvi.com\/samacheer-kalvi-8th-maths-guide-chapter-7-ex-7-2\/","title":{"rendered":"Samacheer Kalvi 8th Maths Guide Chapter 7 Information processing Ex 7.2"},"content":{"rendered":"

Tamilnadu State Board New Syllabus Samacheer Kalvi 8th Maths Guide<\/a> Pdf Chapter 7 Information processing Ex 7.2 Text Book Back Questions and Answers, Notes.<\/p>\n

Tamilnadu Samacheer Kalvi 8th Maths Solutions Chapter 7 Information processing Ex 7.2<\/h2>\n

Question 1.
\nUsing repeated division method, find the HCF of the following:
\n(i) 455 and 26
\nAnswer:
\n\"Samacheer
\nStep 1: The larger number should be dividend 455 & smaller number should be divisor = 26
\nStep 2: After 1st division, the remainder becomes new divisor & the previous divisor becomes next dividend.
\nStep 3: This is done till remainder is zero.
\nStep 4: The last divisor is the HCF L.
\n\u2234 Ans: HCF is 13.<\/p>\n

\"Samacheer<\/p>\n

(ii) 392 and 256
\nAnswer:
\n256 is smaller, so it is the 1st divisor
\n\"Samacheer
\n\u2234 HCF = 8<\/p>\n

(iii) 6765 and 610
\nAnswer:
\n\"Samacheer
\n\u2234 HCF = 5<\/p>\n

\"Samacheer<\/p>\n

(iv) 184, 230 and 276
\nAnswer:
\nFirst let us take 184 & 230
\n\"Samacheer
\n\u2234 46 is the HCF of 184 and 230
\nNow the HCF of the first two numbers is the dividend for the third number.
\n\"Samacheer
\n\u2234 Ans: HCF of 184, 230 & 276 is 46<\/p>\n

Question 2.
\nUsing repeated subtraction method, find the HCF of the following:
\n(i) 42 and 70
\nAnswer:
\nLet number be m & n m > n
\nWe do, m – n & the result of subtraction becomes new \u2018m\u2019. if m becomes less than n,
\nwe do n – m and then assign the result as n. We should do this till m n. When m = n then \u2018m\u2019 is the HCF.
\n42 and 70
\nm = 70 n = 42
\n70 – 42 = 28<\/p>\n

now m = 42, n = 28
\n42 – 28 = 14.<\/p>\n

now m = 28, n = 14
\n28 – 14 = 14.<\/p>\n

now m = 14. n = 14;
\nwe stop here as m = n
\n\u2234 HCF of 42 & 70 is 14<\/p>\n

\"Samacheer<\/p>\n

(ii) 36 and 80
\nAnswer:
\n\"Samacheer
\n28 – 8 = 20
\n20 – 8 = 12
\n12 – 8 = 4
\n8 = 4 = 4
\nnow m = n = 4
\n\u2234 HCF is 4<\/p>\n

(iii) 280 and 420
\nAnswer:
\nLet m = 420, n = 280
\nm – n = 420 – 280 = 140
\nnow m = 280, n = 140
\nm – n = 280 – 140 = 140
\nnow m = n = 140
\n\u2234 HCF is 140<\/p>\n

\"Samacheer<\/p>\n

(iv) 1014 and 654
\nAnswer:
\nLet m = 1014, n = 654
\nm – n = 1014 – 654 = 360
\nnow m = 654, n = 360
\nm – n = 654 – 360 = 294
\nnow m = 360, n = 294
\nm – n = 360 – 294 = 66
\nnow m = 294 n = 66
\nm – n = 294 – 66 = 228
\nnow m = 66, n = 228
\nn – m = 228 – 66 = 162
\nnow m = 162, n = 66
\n= 162 – 66 = 96
\nn – m = 96 – 66 = 30
\nSimilarly, 66 – 30 = 36
\n36 – 30 = 6
\n30 – 6 = 24
\n24 – 6 = 18
\n18 – 6 = 12
\n12 – 6 = 6 now m = n
\n\u2234 HCF of 1014 and 654 is 6<\/p>\n

\"Samacheer<\/p>\n

Question 3.
\nDo the given problems by repeated subtraction method and verify the result.
\n(i) 56 and 12
\n\"Samacheer
\nAnswer:
\nLet n = 56 & n = 12
\nm – n = 56 – 12 = 44
\nnow m = 44, n = 12
\nm – n = 44 – 12 = 32
\nm – n = 32 – 12 = 20
\nm – n = 20 – 12 = 8
\nn – m = 12 – 84
\nm – n = 8 – 4 = 4. now m = n
\n\u2234 HCF of 56 & 12 is 4<\/p>\n

\"Samacheer<\/p>\n

(ii) 320, 120 and 95
\n\"Samacheer
\nAnswer:
\nLet us take 320 & 120 first m = 320, n = 120
\nm – n = 320 – 120 = 200
\nm = 200, n = 120
\n\u2234 m – n = 200 – 120 = 80
\n120 – 80 = 40
\n80 – 40 = 40
\n\u2234 m = n = 40 \u2192 HCF of 320, 120
\nNow let us find HCF of 40 & 95
\nm = 95, n = 40
\n\u2234 m – n = 95 – 40 = 55
\n55 – 40 = 15
\n40 – 15 = 25
\n25 – 15 = 10
\n15 – 10 = 5
\nHCF of 40 & 95 is 5
\n10 – 5 = 5
\n\u2234 HCF of 320 120 & 95 is 5<\/p>\n

\"Samacheer<\/p>\n

Question 4.
\nKalai wants to cut identical squares as big as she can, from a piece of paper measuring 168mm and by 196mm. What is the length of the side of the biggest square? (To find HCF using repeated subtraction method)
\nAnswer:
\nSides are 168 & 196
\nTo find HCF of 168 & 196, we are to use repeated subtraction method.
\n\u2234 m = 196, n = 168
\nm – n = 196 – 168 = 28<\/p>\n

now n = 28, m = 168
\nm – n = 168 – 28 = 140<\/p>\n

now m = 140, n = 28
\nm – n = 140 – 28 = 112<\/p>\n

now m = 112, n = 28
\nm – n = 112 – 28 = 84<\/p>\n

now m = 84, n = 28
\nm – n = 84 – 28 = 56<\/p>\n

now m = 56, n = 28
\nm – n = 56 – 28 = 28
\n\u2234 HCF is 28
\n\u2234 Length of biggest square is 28<\/p>\n

\"Samacheer<\/p>\n

Objective Type Questions<\/p>\n

Question 5.
\nWhat is the eleventh Fibonacci number?
\n(a) 55
\n(b) 77
\n(c) 89
\n(d) 144
\nAnswer:
\n(c) 89
\nHint:
\n\"Samacheer
\n\u2234 11th<\/sup> Fibonacci number is 89<\/p>\n

Question 6.
\nIf F(n) is a Fibonacci number and n = 8, which of the following is true?
\n(a) F(8) = F(9) + F( 10)
\n(b) F(8) = F(7) + F(6)
\n(c) F(8) = F(10) \u00d7 F(9)
\n(d) F(8) = F(7) – F(6)
\nAnswer:
\n(b) F(8) = F(7) + F(6)
\nHint:
\nGiven F(n) is a Fibonacci number & n = 8
\n\u2234 F(8) = F(7) + F (6) as any term in Fibonacci series is the sum of preceding 2 terms<\/p>\n

\"Samacheer<\/p>\n

Question 7.
\nEvery 3rd<\/sup> number of the Fibonacci sequence is a multiple of_______
\n(a) 2
\n(b) 3
\n(c) 5
\n(d) 8
\nAnswer:
\n(a) 2
\nHint:
\nEvery 3rd<\/sup> number in Fibonacci sequence is a multiple of 2<\/p>\n

Question 8.
\nEvery _____ number of the Fibonacci sequence is a multiple of 8
\n(a) 2th<\/sup>
\n(b) 4th<\/sup>
\n(c) 6th<\/sup>
\n(d) 8th<\/sup>
\nAnswer:
\n(c) 6th<\/sup><\/p>\n

\"Samacheer<\/p>\n

Question 9.
\nThe difference between the 18th<\/sup> and 17th<\/sup> Fibonacci number is
\n(a) 233
\n(b) 377
\n(c) 610
\n(d) 987
\nAnswer:
\n(d) 987
\nHint:
\nF(18) = F(17) + F(16)
\nF(18) – F(17) = F(16) = F(15) + F(14)
\n= 610 + 377 = 987<\/p>\n

Question 10.
\nCommon prime factors of 30 and 250 are
\n(a) 2 \u00d7 5
\n(b) 3 \u00d7 5
\n(c) 2 \u00d7 3 \u00d7 5
\n(d) 5 \u00d7 5
\nAnswer:
\n(a) 2 \u00d7 5
\nPrime factors of 30 are 2 \u00d7 3 \u00d7 5
\nPrime factors of 250 are 5 \u00d7 5 \u00d7 5 \u00d7 2
\n\u2234 Common prime factors are 2 \u00d7 5<\/p>\n

\"Samacheer<\/p>\n

Question 11.
\nCommon prime factors of 36,60 and 72 are
\n(a) 2 \u00d7 2
\n(b) 2 \u00d7 3
\n(c) 3 \u00d7 3
\n(d) 3 \u00d7 2 \u00d7 2
\nAnswer:
\n(d) 3 \u00d7 2 \u00d7 2
\nHint:
\nPrime factors of 36 are 2 \u00d7 2 \u00d7 3 \u00d7 3
\nPrime factors of 60 are 2 \u00d7 2 \u00d7 3 \u00d7 5
\nPrime factors of 72 are 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3
\n\u2234 Common prime factors are 2 \u00d7 2 \u00d7 3<\/p>\n

Question 12.
\nTwo numbers are said to be co-prime numbers if their HCF is
\n(a) 2
\n(b) 3
\n(c) 0
\n(d) 1
\nAnswer:
\n(d) 11<\/p>\n","protected":false},"excerpt":{"rendered":"

Tamilnadu State Board New Syllabus Samacheer Kalvi 8th Maths Guide Pdf Chapter 7 Information processing Ex 7.2 Text Book Back Questions and Answers, Notes. Tamilnadu Samacheer Kalvi 8th Maths Solutions Chapter 7 Information processing Ex 7.2 Question 1. Using repeated division method, find the HCF of the following: (i) 455 and 26 Answer: Step 1: …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/posts\/9472"}],"collection":[{"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/comments?post=9472"}],"version-history":[{"count":1,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/posts\/9472\/revisions"}],"predecessor-version":[{"id":48358,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/posts\/9472\/revisions\/48358"}],"wp:attachment":[{"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/media?parent=9472"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/categories?post=9472"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheer-kalvi.com\/wp-json\/wp\/v2\/tags?post=9472"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}