Tamilnadu State Board New Syllabus Samacheer Kalvi 8th Maths Guide Pdf Chapter 6 Statistics Ex 6.3 Text Book Back Questions and Answers, Notes.

## Tamilnadu Samacheer Kalvi 8th Maths Solutions Chapter 6 Statistics Ex 6.3

Miscellaneous Practice Problems

Question 1.

Draw a pie chart for the given table.

Answer:

Converting the area in percentage into components parts of 360°. we have.

Continental Area.

Question 2.

The data on modes of transport used by the students to come to school are given below. Draw a pie chart for the data.

Answer:

Converting the percentage into components parts of 360°. we have

Mode of Transport by students.

Question 3.

Draw a histogram for the given frequency distribution.

Answer:

The given distribution is discontinuous.

Lower boundary = lower limit – \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)

= 41 – \(\frac { 1 }{ 2 }\)(1) = 40.5

Upper boundary = Upper limit + \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)

= 45 + \(\frac { 1 }{ 2 }\)(1) = 45.5

Now continuous frequency table is as below

Question 4.

Draw a histogram and the frequency polygon in the same diagram to represent the following data.

Answer:

The given distribution is discontinuous.

Lower boundary = lower limit – \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)

= 50 – \(\frac { 1 }{ 2 }\)(1) = 49.5

Upper boundary = Upper limit + \(\frac { 1 }{ 2 }\)(gap between the adjacent class interval)

= 55 + \(\frac { 1 }{ 2 }\)(1) = 55.5

∴ The continuous frequency table is as below.

Challenging problems

Question 5.

Form a continuous frequency distribution table and draw histogram from the following data.

Age (in years) | No of persons |

Under 5 | 1 |

Under 10 | 12 |

Under 15 | 19 |

Under 20 | 26 |

Under 25 | 27 |

Under 30 | 35 |

Under 35 | 38 |

Under 40 | 45 |

Under 45 | 48 |

Under 50 | 53 |

Answer:

Converting into continuous distribution we have

Class interval | No. of persons |

0 – 5 | 1 |

5 – 10 | 11 |

10 – 15 | 7 |

15 – 20 | 7 |

20 – 25 | 1 |

25 – 30 | 8 |

30 – 35 | 3 |

35 – 40 | 7 |

40 – 45 | 3 |

45 – 50 | 5 |

Total | 53 |

Question 6.

A rupee spent in a cloth manufacturing company is distributed as follows. Represent this in a pie chart.

Particulars | Paise |

Farmer | 20 |

Spinner | 35 |

Dyer | 15 |

Weaver | 15 |

Printer | 05 |

Salary | 10 |

Answer:

1 Rupee = 100 paise.

Expenditure of a cloth manufacturing company.

Question 7.

Draw a histogram for the following data.

Answer:

Since mid values are given, the given distributors is discontinuous.

Lower boundary lower limit – \(\frac { 1 }{ 2 }\)(gap between the adjacent class interval)

= 15 – \(\frac { 1 }{ 2 }\)(10) = 10

Upper boundary = Upper limit + (gap between the adjacent class interval)

= 15 + \(\frac { 1 }{ 2 }\)(10) = 20

The continuous distribution will he as folIows.