Tamilnadu State Board New Syllabus Samacheer Kalvi 8th Maths Guide Pdf Chapter 6 Statistics Ex 6.3 Text Book Back Questions and Answers, Notes.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Chapter 6 Statistics Ex 6.3

Miscellaneous Practice Problems

Question 1.
Draw a pie chart for the given table.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 1
Answer:
Converting the area in percentage into components parts of 360°. we have.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 2
Continental Area.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 3

Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Question 2.
The data on modes of transport used by the students to come to school are given below. Draw a pie chart for the data.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 4
Answer:
Converting the percentage into components parts of 360°. we have
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 5
Mode of Transport by students.
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Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Question 3.
Draw a histogram for the given frequency distribution.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 7
Answer:
The given distribution is discontinuous.
Lower boundary = lower limit – \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)
= 41 – \(\frac { 1 }{ 2 }\)(1) = 40.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)
= 45 + \(\frac { 1 }{ 2 }\)(1) = 45.5
Now continuous frequency table is as below
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 8
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 9

Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Question 4.
Draw a histogram and the frequency polygon in the same diagram to represent the following data.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 10
Answer:
The given distribution is discontinuous.
Lower boundary = lower limit – \(\frac { 1 }{ 2 }\) (gap between the adjacent class interval)
= 50 – \(\frac { 1 }{ 2 }\)(1) = 49.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 }\)(gap between the adjacent class interval)
= 55 + \(\frac { 1 }{ 2 }\)(1) = 55.5
∴ The continuous frequency table is as below.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 11
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 12

Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Challenging problems

Question 5.
Form a continuous frequency distribution table and draw histogram from the following data.

Age (in years)No of persons
Under 51
Under 1012
Under 1519
Under 2026
Under 2527
Under 3035
Under 3538
Under 4045
Under 4548
Under 5053

Answer:
Converting into continuous distribution we have

Class intervalNo. of persons
0 – 51
5 – 1011
10 – 157
15 – 207
20 – 251
25 – 308
30 – 353
35 – 407
40 – 453
45 – 505
Total53

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Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Question 6.
A rupee spent in a cloth manufacturing company is distributed as follows. Represent this in a pie chart.

ParticularsPaise
Farmer20
Spinner35
Dyer15
Weaver15
Printer05
Salary10

Answer:
1 Rupee = 100 paise.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 14
Expenditure of a cloth manufacturing company.
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Samacheer Kalvi 8th Maths Guide Chapter 6 Statistics Ex 6.3

Question 7.
Draw a histogram for the following data.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 16
Answer:
Since mid values are given, the given distributors is discontinuous.
Lower boundary lower limit – \(\frac { 1 }{ 2 }\)(gap between the adjacent class interval)
= 15 – \(\frac { 1 }{ 2 }\)(10) = 10
Upper boundary = Upper limit + (gap between the adjacent class interval)
= 15 + \(\frac { 1 }{ 2 }\)(10) = 20
The continuous distribution will he as folIows.
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 17
Samacheer Kalvi 8th Maths Guide Answers Chapter 6 Statistics Ex 6.3 18