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## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1

Question 1.
Fill in the blanks.
(i) 250 ml + $$\frac{1}{2}$$ ml = _____ l.
(ii) 150 kg 200 g + 55 kg 750 g = ____ kg ____ g.
(iii) 20 l – 1 l 500 ml = ____ l ___ ml
(iv) 450 ml × 5 = ____ l ____ ml.
(v) 50 Kg ÷ 100 g = ______
Solution:
(i) $$\frac{3}{4}$$ l
(ii) 205 kg 950 g
(iii) 18 l 500 ml
(iv) 2l 250 ml
(v) 500 Question 2.
True or False.
(i) Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg.
(ii) Meena bought 250 ml of buttermilk which is equal to 2.5 l.
(iii) Karkuzhali’s bag 1 kg 250 g and Poongkodi’s bag 2 kg 750 g. The total weight of their bags 4 kg.
(iv) Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.
(v) Gayathri bought 1 kg of birthday cake. She shared 450 g with her friends. The weight of cake remaining is 650 g.
Solution:
(i) True
(ii) False
(iii) True
(iv) True
(v) False Question 3.
Convert into indicated units:
(i) 10 l and 50 ml into ml
(ii) 4 km and 300 m into m
(iii) 300 mg into g
Solution:
(i) 10 l and 50 ml
= 10 × 1000 ml + 50 ml
= (10000 + 50)ml
= 10050 ml

(ii) 4 km and 300 m
= 4 × 1000 + 300 m
= (4000 + 300) m
= 4300 m

(iii) 300 mg
= $$\frac{300}{1000}$$g
= 0.3 g Question 4.
Convert into higher units:
(i) 13000 mm
(km, m, cm)
Solution:
13000 mm
= $$\frac{13000}{10}$$ cm
= 1300 cm
= $$\frac{13000}{1000}$$ m = 13000 mm
= 13 m
= $$\frac{13000}{1000000}$$ km = 13000 mm
= 0.013 km

(ii) 8257 ml (kl, l)
Solution:
8257 ml
= $$\frac{8257}{1000}$$ l
= 8.257 l
= 8257 ml
= $$\frac{8257}{1000000}$$ kl
= 0.008257 kl Question 5.
Convert into lower units:
(i) 15 km (m, cm, mm)
(ii) 12 kg (g, mg)
Solution:
(i) 15 km = 15 × 1000 m = 15000 m
15 km = 15 × 100000 cm
= 1500000 cm
15 km = 15 × 1000000 mm
= 15000000 mm

(ii) 12 kg (g, mg)
Solution:
12 kg = 12 × 1000 g
= 12000 g
12 kg = 12 × 1000000 mg
= 12000000 mg

Question 6.
Compare and put > or < or = in the following:
(i) 800 g + 150 g ____ 1 kg
(ii) 600 ml + 400 ml ____ 1 l
(iii) 6 m 25 cm ____ 600 cm + 25 cm
(iv) 88 cm ____ 8 m 8 cm
(v) 55 g ____ 550 mg
Solution:
(i) 800 g + 150g < 3kg
(ii) 600 ml + 400 ml = 1 l
(iii) 6 m 25 cm = 600 cm + 25 cm
(iv) 88 cm < 8 m 8 cm
(v) 55 g > 550 mg Question 7.
Geetha brought 2 l and 250 ml of water in a bottle. Her friend drank 300 ml from it. How much of water is remaining in the bottle?
Solution:
Quantity of water Geetha brought = 2 l 250 ml
= 2 × 1000 + 250 ml
= 2000 + 250 ml
= 2,250 ml.
Quantity of water her friend drank = 300 ml
Remaining water = 2250 – 300 = 1950 ml. = 1 litre 950 ml.
Remaining water = 1 litre 950 ml.

Question 8.
Thenmozhi’s height is 1.25 m now she grows 5 cm every year. What would be her height after 6 years?
Solution:
Thenmozhi’s present height = 1.25 m
Rate of growth per year = 5 cm
Her growth in 6 years = 5 cm × 6 = 30 cm.
After 6 years her height = 1.25 m + 30 cm
= 1.25 × 100 + 30 cm
= 125 + 30 cm
= 155 cm.
∴ After 6 years Thenmozhi’s height will be 155 cm. Question 9.
Priya bought 22$$\frac { 1 }{ 2 }$$ kg of onion, Krishna bought 18$$\frac { 3 }{ 4 }$$ kg of onion and Sethu bought 9 kg 250 g of onion. What is the total weight of onion did they buy?
Solution:
Priya’s weight = 22 kg 500 g
Krishna’s weight = 18 kg 750 g
Sethu’s weight = 9 kg 250 g
Total weight = 49 kg 1500 g = 49 kg + 1 kg 500 g = 50 kg + 500 g.
Their total weight = 50 kg 500 g.

Question 10.
Maran walks 1.5 km every day to reach the school while Mahizhan walks 1400 m. Who walks more distance and by how much?
Solution:
Distance which Maran walks = 1.5 km = 1.5 × 1000 m = 1500 m
The distance which Mahizhan walks = 1400 m.
Here 1500 > 1400
∴ Difference = 1500 – 1400 = 100 m.
∴ Maran walks more distance = 100 m. Question 11.
In a JRC one day camp, 150 gm of rice and 15 ml oil are needed for a student. If there are 40 students to attend the camp how much rice and oil are needed?
Solution:
Rice needed for one student = 150 g
Rice needed for 40 students = 150 g × 40 = 6000 g. = $$\frac{6000}{1000}$$ kg = 6 kg.
Oil needed for one student = 15 ml
Oil needed for 40 students = 15 ml × 40 = 600 ml. = $$\frac{600}{1000}$$ l = 0.6 l
∴ For the camp 6 kg of rice and 0.6 l of oil needed.

Question 12.
In a school, 200 litres of lemon juice is prepared. If 250 ml lemon juice is given to each student, how many students get the juice?
Solution:
Total lemon juice prepared = 200 l = 200 × 1000 ml = 2,00,000 ml.
∴ Quantity of Lemon juice given to one student = 250 ml.
∴ Number of students can get = $$\frac{2,00,000}{250}$$ = 800
∴ 800 students can get the lemon juice. Question 13.
How many glasses of the given capacity will fill a 2 litre jug?
(i) 100 ml ___
(ii) 50 ml ____
(iii) 500 ml ____
(iv) 1 l ____
(v) 250 ml ____
Solution:
2 litre = 2 × 1000 ml = 2000 ml.
(i) 100 ml
$$\frac{2000}{100}=20$$
20 glasses of 100 ml.
(ii) 50 ml
$$\frac{2000}{50}=40$$
40 glasses of 50 ml
(iii) 500 ml
$$\frac{2000}{500}=4$$
4 glasses of 500 ml
(iv) 1 l
$$\frac{2 l}{1 l}=2$$
2 glasses of 1 l.
(v) 250 ml
$$\frac{2000}{250}=8$$
8 glasses of 250 ml can fill the jug.

Objective Type Questions

Question 14.
9 m 4 cm is equal to ……..
(i) 94 cm
(ii) 904 cm
(iii) 9.4 cm
(iv) 0.94 cm
Solution:
(ii) 904 cm Question 15.
1006 g is equal to ____
(a) 1 kg 6 g
(b) 10 kg 6 g
(c) 100 kg 6 g
(d) 1 kg 600 g
Solution:
(a) 1 kg 6 g

Question 16.
Every day 150 l of water is sprayed in the garden. Water sprayed in a week is ……
(i) 700 l
(ii) 1000 l
(iii) 950 l
(iv) 1050 l
Solution:
(iv) 1050 l

Question 17.
Which is the greatest 0.007 g, 70 mg, 0.07 cg?
(a) 0.07 cg
(b) 0.007 g
(c) 70 mg
(d) all are equal
Solution:
(d) all are equal Question 18.
7 km – 4200 m is equal to ……….
(i) 3 km 800 m
(ii) 2 km 800 m
(iii) 3 km 200 m
(iv) 2 km 200 m
Solution:
(ii) 2 km 800 m